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Baltic Way 2017 · Problem 12

Geometry

Line ℓ\ell touches circle S1S_{1} in the point XX and circle S2S_{2} in the point YY. We draw a line mm which is parallel to ℓ\ell and intersects S1S_{1} in a point PP and S2S_{2} in a point QQ. Prove that the ratio XP/YQX P / Y Q does not depend on the choice of mm.

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Topics

Circles and tangency · Constructions, loci, concurrency and collinearity

Solutions

Solution

Let TT be the second intersection point of PQP Q and S1S_{1} and RR be the second intersection point of PQP Q and S2S_{2}. Let ∠PXT=α\angle P X T=\alpha, ∠RYQ=β\angle R Y Q=\beta. It is evident that PX=XT,RY=YQP X=X T, R Y=Y Q. Calculate the ratio area PXT/{ }_{P X T} / area RYQ_{R Y Q} by two different ways. First,

area⁡PXTarea⁡RYQ=XP2sin⁡αYQ2sin⁡β\frac{\operatorname{area}_{P X T}}{\operatorname{area}_{R Y Q}}=\frac{X P^{2} \sin \alpha}{Y Q^{2} \sin \beta}

Second,

Equating these expressions we obtain

area⁡PXTarea⁡RYQ=PTRQ=2R1sin⁡α2R2sin⁡β\frac{\operatorname{area}_{P X T}}{\operatorname{area}_{R Y Q}}=\frac{P T}{R Q}=\frac{2 R_{1} \sin \alpha}{2 R_{2} \sin \beta} XPYQ=R1R2\frac{X P}{Y Q}=\sqrt{\frac{R_{1}}{R_{2}}}

Contest context

Results from Baltic Way 2017

11 teams

Mean score
4.1 / 5
Scores of 4 or 5
9 / 11
Estonia
5 / 5

Score distribution

02
10
20
30
40
59
All team scores
TeamScore
St. Petersburg5 / 5
Germany5 / 5
Poland5 / 5
Denmark0 / 5
Estonia5 / 5
Lithuania5 / 5
Sweden5 / 5
Norway5 / 5
Finland5 / 5
Iceland5 / 5
Latvia0 / 5