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Baltic Way 1993 · Problem 9

Algebra

Solve the system of equations:

{x5=y+y5y5=z+z5z5=t+t5t5=x+x5.\left\{\begin{array}{l} x^{5}=y+y^{5} \\ y^{5}=z+z^{5} \\ z^{5}=t+t^{5} \\ t^{5}=x+x^{5} . \end{array}\right.
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Topics

Polynomials · Algebraic manipulation

Solutions

Solution

Solution: Adding all four equations we get x+y+z+t=0x+y+z+t=0. On the other hand, the numbers x,y,z,tx, y, z, t are simultaneously positive, negative or equal to zero. Thus, x=y=z=t=0x=y=z=t=0 is the only solution.

Contest context

Results from Baltic Way 1993

8 teams

Mean score
4.6 / 5
Scores of 4 or 5
7 / 8
Estonia
5 / 5

Score distribution

00
10
21
30
40
57
All team scores
TeamScore
Poland5 / 5
Latvia5 / 5
Estonia5 / 5
Sweden2 / 5
Lithuania5 / 5
Finland5 / 5
Iceland5 / 5
Denmark5 / 5