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Baltic Way 1992 · Problem 5

Number Theory

Given that a2+b2+(a+b)2=c2+d2+(c+d)2a^{2}+b^{2}+(a+b)^{2}=c^{2}+d^{2}+(c+d)^{2}, prove that a4+b4+(a+b)4=c4+d4+(c+d)4a^{4}+b^{4}+(a+b)^{4}=c^{4}+d^{4}+(c+d)^{4}.

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Review

Topics

Divisibility and factorization

Solutions

Solution

Solution:

Use the identity (a2+b2+(a+b)2)2=2(a4+b4+(a+b)4)\left(a^{2}+b^{2}+(a+b)^{2}\right)^{2}=2\left(a^{4}+b^{4}+(a+b)^{4}\right).

Contest context

Results from Baltic Way 1992

8 teams

Mean score
4.5 / 5
Scores of 4 or 5
7 / 8
Estonia
5 / 5

Score distribution

00
11
20
30
40
57
All team scores
TeamScore
Denmark5 / 5
St. Petersburg5 / 5
Poland5 / 5
Latvia5 / 5
Iceland5 / 5
Lithuania1 / 5
Estonia5 / 5
Sweden5 / 5