Balti Tee 1992 · Ülesanne 19
Geomeetria
Let be a circle in the plane. Let and be non-intersecting circles touching internally at points and respectively. Let be a common tangent of and , touching them at points and respectively, such that both and are on the same side of . Let be the point of intersection of and . Show that lies on .
Kui oled valmis
Ülevaatematerjal muutub kättesaadavaks järgmise päevaülesannete komplektiga.
Ülevaade
Teemad
Ringjooned ja puutujad · Teisendused
Lahendused
Lahendus
Solution:
Let be the second intersection point of the line and the circle (see Figure 3). Consider the homothety with centre which maps onto . This homothety maps the circle onto and the tangent line of onto the tangent line of the circle at . Let us do the same with the circle and the line : let be their intersection point and consider the homothety with centre , mapping onto , onto and onto the tangent of at point . Since the tangents of at and are both parallel to , they must coincide, and so must the points and .
Võistluse kontekst
Balti Tee tulemused 1992
8 võistkonda
- Keskmine tulemus
- 3,9 / 5
- 4 või 5 punkti
- 6 / 8
- Eesti
- 0 / 5
Punktijaotus
Kõigi võistkondade punktid
| Võistkond | Punktid |
|---|---|
| Denmark | 1 / 5 |
| St. Petersburg | 5 / 5 |
| Poland | 5 / 5 |
| Latvia | 5 / 5 |
| Iceland | 5 / 5 |
| Lithuania | 5 / 5 |
| Estonia | 0 / 5 |
| Sweden | 5 / 5 |