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Baltic Way 2021 · Shortlist problem

Geometry

Let ω1\omega_1 and ω3\omega_3 be two circles, touching externally in a common point PP. Let further ω2\omega_2 and ω4\omega_4 be two circles touching externally in PP. Suppose that for i∈{1,2,3,4}i \in \{1, 2, 3, 4\} ωi\omega_i intersect ω(i(mod4))+1\omega_{(i \pmod 4)+1} again in AiA_i. Let ℓ1\ell_1 be the common tangent of ω1\omega_1 and ω3\omega_3 and ℓ2\ell_2 be the common tangent of ω2\omega_2 and ω4\omega_4. Show that A1,A2,A3A_1, A_2, A_3 and A4A_4 are con-cyclic if and only if ℓ1\ell_1 and ℓ2\ell_2 are orthogonal.

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Topics

Circles and tangency · Angles and distances · Cyclic geometry

Solutions

Solution

Solution. In figure 15, we have

∠CNK=∠ANK=∠AOK=2∠ABK=2∠NBK.\angle CNK = \angle ANK = \angle AOK = 2\angle ABK = 2\angle NBK.

Hence triangle BNKBNK is isosceles, so NK=NB=NCNK = NB = NC, and therefore ∠BKC\angle BKC is right. If we let KCKC intersect ω\omega at K′K', we see that K′,OK', O and BB are collinear, as ∠BKK′\angle BKK' is right. Let us note that CC lies on OXOX. Indeed,

Pow(C,AONKX)=AC⋅CN=12AC⋅CB=CM⋅CB=Pow(C,BOMLX).\mathrm{Pow}(C, AONKX) = AC \cdot CN = \frac{1}{2} AC \cdot CB = CM \cdot CB = \mathrm{Pow}(C, BOMLX).

Now,

∠LXC=∠LXO=∠LBO=∠LBK′=∠LKK′=∠LKC\angle LXC = \angle LXO = \angle LBO = \angle LBK' = \angle LKK' = \angle LKC

Showing that XLCKXLCK is cyclic, as required.

Diagram for the mathnet 01i3 1 of bw-cand-2021-mn-01i3.