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Baltic Way 2011 · Shortlist problem

Geometry

Suppose that the quadrilateral ABCDABCD satisfies ∠ABD=30∘\angle ABD = 30^\circ, ∠CDB=20∘\angle CDB = 20^\circ and ∠BCA=∠ACD=40∘\angle BCA = \angle ACD = 40^\circ. Determine ∠DAC\angle DAC.

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Topics

Angles and distances · Constructions, loci, concurrency and collinearity

Solutions

Solution

Let EE be the intersection point of the diagonals ACAC and BDBD. Let EFEF be the bisector of ∠DEC\angle DEC, with FF on DCDC.

Diagram for the mathnet 0190 1 of bw-cand-2011-mn-0190.

Then the triangles BECBEC and CFECFE are congruent (EFCBEFCB is a kite). So EF=EB=EAEF = EB = EA, and ADFEADFE is a kite. It follows that ∠DAC=100∘\angle DAC = 100^\circ.