Baltic Way 2022 · Problem 3
Algebra
We call a two-variable polynomial secretly one-variable if there exist polynomials and such that and (e.g. and are secretly one-variable, but is not).
Prove or disprove the following statement: If is a polynomial such that both and can be written as the product of two non-constant polynomials, then is secretly one-variable.
Note: All polynomials are assumed to have real coefficients.
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Review
Topics
Polynomials · Sequences and recurrences
Solutions
No verified local solution is currently available.
Contest context
Results from Baltic Way 2022
10 teams
- Mean score
- 0.5 / 5
- Scores of 4 or 5
- 1 / 10
- Estonia
- 5 / 5
Score distribution
09
10
20
30
40
51
All team scores
| Team | Score |
|---|---|
| Poland | 0 / 5 |
| Germany | 0 / 5 |
| Lithuania | 0 / 5 |
| Estonia | 5 / 5 |
| Denmark | 0 / 5 |
| Latvia | 0 / 5 |
| Sweden | 0 / 5 |
| Norway | 0 / 5 |
| Finland | 0 / 5 |
| Iceland | 0 / 5 |