Baltic Way 2019 · Problem 15
Geometry
Let , and consider a (not necessarily convex) polygon in the plane. Suppose that, for each , there is a unique vertex among that lies closest to it. The polygon is then said to be hostile if for all (where , ).
(a) Prove that no hostile polygon is convex.
(b) Find all for which there exists a hostile -gon.
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Review
Topics
Combinatorial geometry and dissections
Solutions
No verified local solution is currently available.
Contest context
Results from Baltic Way 2019
11 teams
- Mean score
- 1.6 / 5
- Scores of 4 or 5
- 1 / 11
- Estonia
- 2 / 5
Score distribution
04
10
25
31
40
51
All team scores
| Team | Score |
|---|---|
| St. Petersburg | 5 / 5 |
| Poland | 3 / 5 |
| Estonia | 2 / 5 |
| Lithuania | 2 / 5 |
| Germany | 2 / 5 |
| Norway | 0 / 5 |
| Finland | 2 / 5 |
| Denmark | 0 / 5 |
| Sweden | 0 / 5 |
| Latvia | 2 / 5 |
| Iceland | 0 / 5 |