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Balti Tee 2011 · Valikvooru ülesanne

Kombinatoorika

Compute the sum

∑n=1∞Fn10n+1\sum_{n=1}^{\infty} \frac{F_n}{10^{n+1}}

where FnF_n is the nnth Fibonacci number given by F1=F2=1F_1 = F_2 = 1 and Fn+1=Fn+Fn−1F_{n+1} = F_n + F_{n-1} for all n≥2n \geq 2.

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Let

X=∑n=1∞Fn10n+1X = \sum_{n=1}^{\infty} \frac{F_n}{10^{n+1}}

Then

X=1102+1103+2104+3105+5106+8107+13108+…X = \frac{1}{10^2} + \frac{1}{10^3} + \frac{2}{10^4} + \frac{3}{10^5} + \frac{5}{10^6} + \frac{8}{10^7} + \frac{13}{10^8} + \dots

So

10X=110+1102+2103+3104+5105+8106+13107+…10X = \frac{1}{10} + \frac{1}{10^2} + \frac{2}{10^3} + \frac{3}{10^4} + \frac{5}{10^5} + \frac{8}{10^6} + \frac{13}{10^7} + \dots

and

100X=1+110+2102+3103+5104+8105+13106+…100X = 1 + \frac{1}{10} + \frac{2}{10^2} + \frac{3}{10^3} + \frac{5}{10^4} + \frac{8}{10^5} + \frac{13}{10^6} + \dots

Then 100X−10X−X=1100X - 10X - X = 1 (using the basic property of the Fibonacci numbers).

So X=189\text{So } X = \frac{1}{89}