Balti Tee 2010 · Ülesanne 8
Kombinatoorika
In a club with 30 members, every member initially had a hat. One day each member sent his hat to a different member (a member could have received more than one hat). Prove that there exists a group of 10 members such that no one in the group has received a hat from another one in the group.
Kui oled valmis
Ülevaatematerjal muutub kättesaadavaks järgmise päevaülesannete komplektiga.
Ülevaade
Teemad
Värvimised ja konfiguratsioonid · Dirichlet’ printsiip ja ekstremaalargumendid
Lahendused
Lahendus
Let be the given group of people. Consider all subsets such that no member of received a hat from a member of . Among such subsets, let be a subset of maximal cardinality. The assertion of the problem is that .
Let consist of all people that have received a hat from a person belonging to . Now consider any member . Since , no member of sent his hat to . It follows that no member of sent a hat to a person from . But the maximality of implies that some person from sent his hat to a person from the same subset. This means that sent his hat to a person from . Consequently, all members of the subset sent their hats to people in . In particular, has the property described in the beginning. The maximality of gives . Finally, we obviously have , so
or , as desired.
Võistluse kontekst
Balti Tee tulemused 2010
10 võistkonda
- Keskmine tulemus
- 3,6 / 5
- 4 või 5 punkti
- 7 / 10
- Eesti
- 5 / 5
Punktijaotus
Kõigi võistkondade punktid
| Võistkond | Punktid |
|---|---|
| Poland | 4 / 5 |
| Lithuania | 0 / 5 |
| Germany | 5 / 5 |
| Latvia | 5 / 5 |
| Denmark | 5 / 5 |
| Sweden | 5 / 5 |
| Estonia | 5 / 5 |
| Norway | 4 / 5 |
| Finland | 2 / 5 |
| Iceland | 1 / 5 |